Optimal. Leaf size=164 \[ -\frac {494 a^2 \tan (e+f x)}{315 c^5 f (1-\sec (e+f x))}-\frac {179 a^2 \tan (e+f x)}{315 c^5 f (1-\sec (e+f x))^2}-\frac {37 a^2 \tan (e+f x)}{105 c^5 f (1-\sec (e+f x))^3}-\frac {16 a^2 \tan (e+f x)}{63 c^5 f (1-\sec (e+f x))^4}-\frac {4 a^2 \tan (e+f x)}{9 c^5 f (1-\sec (e+f x))^5}+\frac {a^2 x}{c^5} \]
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Rubi [A] time = 0.54, antiderivative size = 164, normalized size of antiderivative = 1.00, number of steps used = 18, number of rules used = 7, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.269, Rules used = {3903, 3777, 3922, 3919, 3794, 3796, 3797} \[ -\frac {494 a^2 \tan (e+f x)}{315 c^5 f (1-\sec (e+f x))}-\frac {179 a^2 \tan (e+f x)}{315 c^5 f (1-\sec (e+f x))^2}-\frac {37 a^2 \tan (e+f x)}{105 c^5 f (1-\sec (e+f x))^3}-\frac {16 a^2 \tan (e+f x)}{63 c^5 f (1-\sec (e+f x))^4}-\frac {4 a^2 \tan (e+f x)}{9 c^5 f (1-\sec (e+f x))^5}+\frac {a^2 x}{c^5} \]
Antiderivative was successfully verified.
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Rule 3777
Rule 3794
Rule 3796
Rule 3797
Rule 3903
Rule 3919
Rule 3922
Rubi steps
\begin {align*} \int \frac {(a+a \sec (e+f x))^2}{(c-c \sec (e+f x))^5} \, dx &=\frac {\int \left (\frac {a^2}{(1-\sec (e+f x))^5}+\frac {2 a^2 \sec (e+f x)}{(1-\sec (e+f x))^5}+\frac {a^2 \sec ^2(e+f x)}{(1-\sec (e+f x))^5}\right ) \, dx}{c^5}\\ &=\frac {a^2 \int \frac {1}{(1-\sec (e+f x))^5} \, dx}{c^5}+\frac {a^2 \int \frac {\sec ^2(e+f x)}{(1-\sec (e+f x))^5} \, dx}{c^5}+\frac {\left (2 a^2\right ) \int \frac {\sec (e+f x)}{(1-\sec (e+f x))^5} \, dx}{c^5}\\ &=-\frac {4 a^2 \tan (e+f x)}{9 c^5 f (1-\sec (e+f x))^5}-\frac {a^2 \int \frac {-9-4 \sec (e+f x)}{(1-\sec (e+f x))^4} \, dx}{9 c^5}-\frac {\left (5 a^2\right ) \int \frac {\sec (e+f x)}{(1-\sec (e+f x))^4} \, dx}{9 c^5}+\frac {\left (8 a^2\right ) \int \frac {\sec (e+f x)}{(1-\sec (e+f x))^4} \, dx}{9 c^5}\\ &=-\frac {4 a^2 \tan (e+f x)}{9 c^5 f (1-\sec (e+f x))^5}-\frac {16 a^2 \tan (e+f x)}{63 c^5 f (1-\sec (e+f x))^4}+\frac {a^2 \int \frac {63+39 \sec (e+f x)}{(1-\sec (e+f x))^3} \, dx}{63 c^5}-\frac {\left (5 a^2\right ) \int \frac {\sec (e+f x)}{(1-\sec (e+f x))^3} \, dx}{21 c^5}+\frac {\left (8 a^2\right ) \int \frac {\sec (e+f x)}{(1-\sec (e+f x))^3} \, dx}{21 c^5}\\ &=-\frac {4 a^2 \tan (e+f x)}{9 c^5 f (1-\sec (e+f x))^5}-\frac {16 a^2 \tan (e+f x)}{63 c^5 f (1-\sec (e+f x))^4}-\frac {37 a^2 \tan (e+f x)}{105 c^5 f (1-\sec (e+f x))^3}-\frac {a^2 \int \frac {-315-204 \sec (e+f x)}{(1-\sec (e+f x))^2} \, dx}{315 c^5}-\frac {\left (2 a^2\right ) \int \frac {\sec (e+f x)}{(1-\sec (e+f x))^2} \, dx}{21 c^5}+\frac {\left (16 a^2\right ) \int \frac {\sec (e+f x)}{(1-\sec (e+f x))^2} \, dx}{105 c^5}\\ &=-\frac {4 a^2 \tan (e+f x)}{9 c^5 f (1-\sec (e+f x))^5}-\frac {16 a^2 \tan (e+f x)}{63 c^5 f (1-\sec (e+f x))^4}-\frac {37 a^2 \tan (e+f x)}{105 c^5 f (1-\sec (e+f x))^3}-\frac {179 a^2 \tan (e+f x)}{315 c^5 f (1-\sec (e+f x))^2}+\frac {a^2 \int \frac {945+519 \sec (e+f x)}{1-\sec (e+f x)} \, dx}{945 c^5}-\frac {\left (2 a^2\right ) \int \frac {\sec (e+f x)}{1-\sec (e+f x)} \, dx}{63 c^5}+\frac {\left (16 a^2\right ) \int \frac {\sec (e+f x)}{1-\sec (e+f x)} \, dx}{315 c^5}\\ &=\frac {a^2 x}{c^5}-\frac {4 a^2 \tan (e+f x)}{9 c^5 f (1-\sec (e+f x))^5}-\frac {16 a^2 \tan (e+f x)}{63 c^5 f (1-\sec (e+f x))^4}-\frac {37 a^2 \tan (e+f x)}{105 c^5 f (1-\sec (e+f x))^3}-\frac {179 a^2 \tan (e+f x)}{315 c^5 f (1-\sec (e+f x))^2}-\frac {2 a^2 \tan (e+f x)}{105 c^5 f (1-\sec (e+f x))}+\frac {\left (488 a^2\right ) \int \frac {\sec (e+f x)}{1-\sec (e+f x)} \, dx}{315 c^5}\\ &=\frac {a^2 x}{c^5}-\frac {4 a^2 \tan (e+f x)}{9 c^5 f (1-\sec (e+f x))^5}-\frac {16 a^2 \tan (e+f x)}{63 c^5 f (1-\sec (e+f x))^4}-\frac {37 a^2 \tan (e+f x)}{105 c^5 f (1-\sec (e+f x))^3}-\frac {179 a^2 \tan (e+f x)}{315 c^5 f (1-\sec (e+f x))^2}-\frac {494 a^2 \tan (e+f x)}{315 c^5 f (1-\sec (e+f x))}\\ \end {align*}
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Mathematica [A] time = 0.99, size = 283, normalized size = 1.73 \[ \frac {a^2 \csc \left (\frac {e}{2}\right ) \csc ^9\left (\frac {1}{2} (e+f x)\right ) \left (-117810 \sin \left (e+\frac {f x}{2}\right )+100002 \sin \left (e+\frac {3 f x}{2}\right )+68670 \sin \left (2 e+\frac {3 f x}{2}\right )-48978 \sin \left (2 e+\frac {5 f x}{2}\right )-23310 \sin \left (3 e+\frac {5 f x}{2}\right )+13662 \sin \left (3 e+\frac {7 f x}{2}\right )+4410 \sin \left (4 e+\frac {7 f x}{2}\right )-2008 \sin \left (4 e+\frac {9 f x}{2}\right )-39690 f x \cos \left (e+\frac {f x}{2}\right )-26460 f x \cos \left (e+\frac {3 f x}{2}\right )+26460 f x \cos \left (2 e+\frac {3 f x}{2}\right )+11340 f x \cos \left (2 e+\frac {5 f x}{2}\right )-11340 f x \cos \left (3 e+\frac {5 f x}{2}\right )-2835 f x \cos \left (3 e+\frac {7 f x}{2}\right )+2835 f x \cos \left (4 e+\frac {7 f x}{2}\right )+315 f x \cos \left (4 e+\frac {9 f x}{2}\right )-315 f x \cos \left (5 e+\frac {9 f x}{2}\right )-135198 \sin \left (\frac {f x}{2}\right )+39690 f x \cos \left (\frac {f x}{2}\right )\right )}{161280 c^5 f} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.46, size = 212, normalized size = 1.29 \[ \frac {1004 \, a^{2} \cos \left (f x + e\right )^{5} - 1811 \, a^{2} \cos \left (f x + e\right )^{4} + 797 \, a^{2} \cos \left (f x + e\right )^{3} + 1457 \, a^{2} \cos \left (f x + e\right )^{2} - 1661 \, a^{2} \cos \left (f x + e\right ) + 494 \, a^{2} + 315 \, {\left (a^{2} f x \cos \left (f x + e\right )^{4} - 4 \, a^{2} f x \cos \left (f x + e\right )^{3} + 6 \, a^{2} f x \cos \left (f x + e\right )^{2} - 4 \, a^{2} f x \cos \left (f x + e\right ) + a^{2} f x\right )} \sin \left (f x + e\right )}{315 \, {\left (c^{5} f \cos \left (f x + e\right )^{4} - 4 \, c^{5} f \cos \left (f x + e\right )^{3} + 6 \, c^{5} f \cos \left (f x + e\right )^{2} - 4 \, c^{5} f \cos \left (f x + e\right ) + c^{5} f\right )} \sin \left (f x + e\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.44, size = 110, normalized size = 0.67 \[ \frac {\frac {1260 \, {\left (f x + e\right )} a^{2}}{c^{5}} + \frac {2520 \, a^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{8} - 840 \, a^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{6} + 441 \, a^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{4} - 180 \, a^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} + 35 \, a^{2}}{c^{5} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{9}}}{1260 \, f} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.84, size = 133, normalized size = 0.81 \[ \frac {a^{2}}{36 f \,c^{5} \tan \left (\frac {e}{2}+\frac {f x}{2}\right )^{9}}-\frac {a^{2}}{7 f \,c^{5} \tan \left (\frac {e}{2}+\frac {f x}{2}\right )^{7}}+\frac {7 a^{2}}{20 f \,c^{5} \tan \left (\frac {e}{2}+\frac {f x}{2}\right )^{5}}-\frac {2 a^{2}}{3 f \,c^{5} \tan \left (\frac {e}{2}+\frac {f x}{2}\right )^{3}}+\frac {2 a^{2}}{f \,c^{5} \tan \left (\frac {e}{2}+\frac {f x}{2}\right )}+\frac {2 a^{2} \arctan \left (\tan \left (\frac {e}{2}+\frac {f x}{2}\right )\right )}{f \,c^{5}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.45, size = 335, normalized size = 2.04 \[ \frac {a^{2} {\left (\frac {10080 \, \arctan \left (\frac {\sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1}\right )}{c^{5}} - \frac {{\left (\frac {270 \, \sin \left (f x + e\right )^{2}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{2}} - \frac {1008 \, \sin \left (f x + e\right )^{4}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{4}} + \frac {2730 \, \sin \left (f x + e\right )^{6}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{6}} - \frac {9765 \, \sin \left (f x + e\right )^{8}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{8}} - 35\right )} {\left (\cos \left (f x + e\right ) + 1\right )}^{9}}{c^{5} \sin \left (f x + e\right )^{9}}\right )} - \frac {2 \, a^{2} {\left (\frac {180 \, \sin \left (f x + e\right )^{2}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{2}} - \frac {378 \, \sin \left (f x + e\right )^{4}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{4}} + \frac {420 \, \sin \left (f x + e\right )^{6}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{6}} - \frac {315 \, \sin \left (f x + e\right )^{8}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{8}} - 35\right )} {\left (\cos \left (f x + e\right ) + 1\right )}^{9}}{c^{5} \sin \left (f x + e\right )^{9}} - \frac {5 \, a^{2} {\left (\frac {18 \, \sin \left (f x + e\right )^{2}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{2}} - \frac {42 \, \sin \left (f x + e\right )^{6}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{6}} + \frac {63 \, \sin \left (f x + e\right )^{8}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{8}} - 7\right )} {\left (\cos \left (f x + e\right ) + 1\right )}^{9}}{c^{5} \sin \left (f x + e\right )^{9}}}{5040 \, f} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.54, size = 146, normalized size = 0.89 \[ \frac {a^2\,\left (\frac {{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^9}{36}-\frac {{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^7\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2}{7}+\frac {7\,{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^5\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^4}{20}-\frac {2\,{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^3\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^6}{3}+2\,\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^8+\left (e+f\,x\right )\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^9\right )}{c^5\,f\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^9} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ - \frac {a^{2} \left (\int \frac {2 \sec {\left (e + f x \right )}}{\sec ^{5}{\left (e + f x \right )} - 5 \sec ^{4}{\left (e + f x \right )} + 10 \sec ^{3}{\left (e + f x \right )} - 10 \sec ^{2}{\left (e + f x \right )} + 5 \sec {\left (e + f x \right )} - 1}\, dx + \int \frac {\sec ^{2}{\left (e + f x \right )}}{\sec ^{5}{\left (e + f x \right )} - 5 \sec ^{4}{\left (e + f x \right )} + 10 \sec ^{3}{\left (e + f x \right )} - 10 \sec ^{2}{\left (e + f x \right )} + 5 \sec {\left (e + f x \right )} - 1}\, dx + \int \frac {1}{\sec ^{5}{\left (e + f x \right )} - 5 \sec ^{4}{\left (e + f x \right )} + 10 \sec ^{3}{\left (e + f x \right )} - 10 \sec ^{2}{\left (e + f x \right )} + 5 \sec {\left (e + f x \right )} - 1}\, dx\right )}{c^{5}} \]
Verification of antiderivative is not currently implemented for this CAS.
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